6h^2-2h-49=0

Solution for 6h^2-2h-49=0 equation:

6h^2-2h-49=0

a = 6; b = -2; c = -49;
Δ = b2-4ac
Δ = -22-4·6·(-49)
Δ = 1180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1180}=\sqrt{4*295}=\sqrt{4}*\sqrt{295}=2\sqrt{295}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{295}}{2*6}=\frac{2-2\sqrt{295}}{12}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{295}}{2*6}=\frac{2+2\sqrt{295}}{12}
$